What is the missing exponent that would make this equation true?%0D%0Ak−5⋅ k2kx=(k0)−2%0D%0A%0D%0A−%0D%0A5%0D%0A⋅%0D%0A %0D%0A%0D%0A2%0D%0A%0D%0A%0D%0A=%0D%0A(%0D%0A%0D%0A0%0D%0A)%0D%0A−%0D%0A2%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0Ax = -5%0D%0Ax = -5%0D%0A%0D%0Ax = -3%0D%0Ax = -3%0D%0A%0D%0Ax = 0%0D%0Ax = 0%0D%0A%0D%0Ax = 2

Answer 1

The missing exponent that would make the equation true is x = -3.