What is the missing exponent that would make this equation true? k5⋅k2kx = (k2)−2 (1 point) Responses x = 11 x = 11 x = 1 x = 1 x = 3 x = 3 x = 6 x = 6 x = 0 x = 0 x = 9
1 answer
The missing exponent that would make the equation true is x = 9.