What is the missing exponent that would make this equation true?
k−5⋅ k2kx=(k0)−2
(1 point)
Responses
x = 2
x = 2
x = 0
x = 0
x = -5
x = -5
x = -3
1 answer
x = -3
k−5⋅ k2kx=(k0)−2
(1 point)
Responses
x = 2
x = 2
x = 0
x = 0
x = -5
x = -5
x = -3
1 answer