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What is the missing exponent that would make this equation true?

k5⋅k2kx = (k2)−2
(1 point)
Responses

x = 1
x = 1

x = 11
x = 11

x = 3
x = 3

x = 6
x = 6

x = 0
x = 0

x = 9

1 answer

The correct missing exponent that would make the equation true is x = 1.
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