What is the missing exponent that would make this equation true?
k5⋅k2kx = (k2)−2
(1 point)
Responses
x = 1
x = 1
x = 11
x = 11
x = 3
x = 3
x = 6
x = 6
x = 0
x = 0
x = 9
1 answer
The correct missing exponent that would make the equation true is x = 1.