What is the missing exponent in the following equation?

e?e65 = e38(

1 answer

To solve for the missing exponent in the equation \( e^? \cdot e^{65} = e^{38} \), we can use the property of exponents that states \( e^a \cdot e^b = e^{a+b} \).

Let's denote the missing exponent as \( x \). The equation can be rewritten as:

\[ e^x \cdot e^{65} = e^{38} \]

Using the property of exponents, we combine the left side:

\[ e^{x + 65} = e^{38} \]

Since the bases are the same, we can set the exponents equal to each other:

\[ x + 65 = 38 \]

Now, we can solve for \( x \):

\[ x = 38 - 65 \] \[ x = -27 \]

Thus, the missing exponent is \( -27 \).

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