the work is the difference in potential energy (mgh):
1210 * 9.8 * 54.0 * sin12.5°
What is the minimum work in joules needed to push a 1210 kg car 54.0 m up a 12.5 degree incline? (Ignore friction.)
1 answer
1 answer
1 answer
1 answer
1 answer
1 answer