work on the cue ball: M*g*mu*1.2 m
and the blue ball M*g*mu*.75m
those added must equal the initial KEnergy on the cue: 1/2 M V^2
so solve for V. Notice M divides out;
What is the minimum velocity in which the cue ball must be hit in order to hit the blue ball into the hole? Assume straight line (cue ball stops moving after hitting the blue ball).
Distance between cue ball and blue ball = 1.2 meters.
Distance between blue ball and hole = 0.75 meters .
Coefficient of friction between ball and table = 0.005.
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