delta x = .05 * 10^-9 m
m = mass of electron
delta p = mass of electron * delta v
delta x * delta p = hbar/2
delta x * m * delta v = h bar/2
delta v = hbar/(delta x * 2 * m electron)
What is the minimum uncertainty in the velocity of an electron that is known to be somewhere between 0.050 nm and 0.10 nm from a proton
1 answer