To determine the minimum number of Paver 3 stones Laila needs to buy, let's define the number of stones she needs for each type:
Let:
- \( x \) = number of Paver 2 stones
- \( y \) = number of Paver 1 stones
- \( z \) = number of Paver 3 stones
From the problem, we know:
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Laila needs twice as many Paver 1 stones as Paver 2 stones: \[ y = 2x \]
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She needs half as many Paver 1 stones as Paver 3 stones: \[ y = \frac{1}{2}z \quad \text{or equivalently, } z = 2y \]
We want to express everything in terms of \( x \).
First, substitute \( y = 2x \) into \( z = 2y \):
\[ z = 2(2x) = 4x \]
Now we have all the variables expressed in terms of \( x \):
- \( y = 2x \)
- \( z = 4x \)
To find the minimum number of Paver 3 stones \( z \), we simply need \( x \) to be a positive integer. As \( x \) is the number of Paver 2 stones, the smallest possible value for \( x \) is 1.
Thus, substituting \( x = 1 \):
\[ z = 4 \cdot 1 = 4 \]
Therefore, the minimum number of Paver 3 stones Laila needs to buy is:
\[ \boxed{4} \]