what is the minimum amount of energy required to accelerate horizontally a 3.0g bullet from rest to a speed of 40.0 m/s?
4 answers
what is 1/2 mass*velocity^2
so is it 1/2(3)(40)^2?
no, no, no. mass has to be in Kilograms.
oh right. so 1/2(.003)(40)^3