Asked by Chioma
What is the median of these numbers
2,6,9,5,2,41,8
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2,6,9,5,2,41,8
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Answered by
GPT-4o mini
To find the median of a set of numbers, you need to follow these steps:
1. **Organize the numbers in ascending order.**
2. **Identify the middle number(s).**
3. **Calculate the median based on whether there is an odd or even number of observations.**
Let's go through these steps with the numbers you provided: \(2, 6, 9, 5, 2, 41, 8\).
### Step 1: Organize in Ascending Order
First, let's sort the numbers:
- The sorted order is: \(2, 2, 5, 6, 8, 9, 41\)
### Step 2: Identify the Middle Number
Now, we need to count how many numbers we have:
- There are 7 numbers in total (which is odd).
### Step 3: Calculate the Median
For an odd set of numbers, the median is the middle number. The middle number can be found using the formula:
\[ \text{Median index} = \frac{n + 1}{2} \]
where \(n\) is the number of observations.
In our case:
\[ \text{Median index} = \frac{7 + 1}{2} = \frac{8}{2} = 4 \]
The 4th number in the sorted list is:
- \(2, 2, 5, \mathbf{6}, 8, 9, 41\)
Therefore, the median is:
\[
\boxed{6}
\]
1. **Organize the numbers in ascending order.**
2. **Identify the middle number(s).**
3. **Calculate the median based on whether there is an odd or even number of observations.**
Let's go through these steps with the numbers you provided: \(2, 6, 9, 5, 2, 41, 8\).
### Step 1: Organize in Ascending Order
First, let's sort the numbers:
- The sorted order is: \(2, 2, 5, 6, 8, 9, 41\)
### Step 2: Identify the Middle Number
Now, we need to count how many numbers we have:
- There are 7 numbers in total (which is odd).
### Step 3: Calculate the Median
For an odd set of numbers, the median is the middle number. The middle number can be found using the formula:
\[ \text{Median index} = \frac{n + 1}{2} \]
where \(n\) is the number of observations.
In our case:
\[ \text{Median index} = \frac{7 + 1}{2} = \frac{8}{2} = 4 \]
The 4th number in the sorted list is:
- \(2, 2, 5, \mathbf{6}, 8, 9, 41\)
Therefore, the median is:
\[
\boxed{6}
\]
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