(what is the meaning of this question)

If the root of the equation x²-8x+m=0 exceeds the other by 4 then the value of m is

1 answer

the roots are

x = (8±√(64-4m))/2 = 4±√(16-m)

So, we have

4+√(16-m) = 4-√(16-m) + 4
2√(16-m) = 4
√(16-m) = 2
16-m = 4
m = 12

So, the function is

x^2-8x+12, and the roots are 2 and 6