First, find the mean of the dataset:
Mean = (4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) / 6
Mean = 35.3 / 6
Mean = 5.88
Next, find the absolute deviation of each number from the mean:
|4.8 - 5.88| = 1.08
|5.9 - 5.88| = 0.02
|6.2 - 5.88| = 0.32
|10.8 - 5.88| = 4.92
|1.2 - 5.88| = 4.68
|6.4 - 5.88| = 0.52
Then, find the mean of these absolute deviations:
Mean Absolute Deviation = (1.08 + 0.02 + 0.32 + 4.92 + 4.68 + 0.52) / 6
Mean Absolute Deviation = 11.54 / 6
Mean Absolute Deviation ≈ 1.9
Therefore, the mean absolute deviation of the dataset is approximately 1.9.
What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.
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The number of words Mr. Ahmad’s students read per minute is 109, 89, 112, 98, 101, 105, 120, 106. What is the mean absolute deviation of the dataset? Round the answer to the nearest tenth.
First, let's find the mean of the dataset:
Mean = (109 + 89 + 112 + 98 + 101 + 105 + 120 + 106) / 8
Mean = 840 / 8
Mean = 105
Next, find the absolute deviation of each number from the mean:
|109 - 105| = 4
|89 - 105| = 16
|112 - 105| = 7
|98 - 105| = 7
|101 - 105| = 4
|105 - 105| = 0
|120 - 105| = 15
|106 - 105| = 1
Then, find the mean of these absolute deviations:
Mean Absolute Deviation = (4 + 16 + 7 + 7 + 4 + 0 + 15 + 1) / 8
Mean Absolute Deviation = 54 / 8
Mean Absolute Deviation ≈ 6.8
Therefore, the mean absolute deviation of the dataset is approximately 6.8.
Mean = (109 + 89 + 112 + 98 + 101 + 105 + 120 + 106) / 8
Mean = 840 / 8
Mean = 105
Next, find the absolute deviation of each number from the mean:
|109 - 105| = 4
|89 - 105| = 16
|112 - 105| = 7
|98 - 105| = 7
|101 - 105| = 4
|105 - 105| = 0
|120 - 105| = 15
|106 - 105| = 1
Then, find the mean of these absolute deviations:
Mean Absolute Deviation = (4 + 16 + 7 + 7 + 4 + 0 + 15 + 1) / 8
Mean Absolute Deviation = 54 / 8
Mean Absolute Deviation ≈ 6.8
Therefore, the mean absolute deviation of the dataset is approximately 6.8.
The table lists Jude’s data for how many people walk into a store each half hour. The mean is 22.3. Identify the absolute deviation for each missing value. Round each value to the nearest tenth.
I'm sorry, but you did not provide the table of Jude's data. Can you please provide the table with the missing values so that I can calculate the absolute deviation for each missing value?
1 answer