To find the mean absolute deviation, first find the mean of the dataset:
(4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) ÷ 6 = 5.7
Next, find the absolute deviation of each value from the mean:
|4.8 - 5.7| = 0.9
|5.9 - 5.7| = 0.2
|6.2 - 5.7| = 0.5
|10.8 - 5.7| = 5.1
|1.2 - 5.7| = 4.5
|6.4 - 5.7| = 0.7
Then, find the mean of these absolute deviations:
(0.9 + 0.2 + 0.5 + 5.1 + 4.5 + 0.7) ÷ 6 ≈ 2.5
Therefore, the mean absolute deviation of the dataset is approximately 2.5.
What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.
7 answers
What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.
To find the mean absolute deviation, first find the mean of the dataset:
(4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) ÷ 6 = 5.7
Next, find the absolute deviation of each value from the mean:
|4.8 - 5.7| = 0.9
|5.9 - 5.7| = 0.2
|6.2 - 5.7| = 0.5
|10.8 - 5.7| = 5.1
|1.2 - 5.7| = 4.5
|6.4 - 5.7| = 0.7
Then, find the mean of these absolute deviations:
(0.9 + 0.2 + 0.5 + 5.1 + 4.5 + 0.7) ÷ 6 ≈ 2.5
Therefore, the mean absolute deviation of the dataset is approximately 2.5.
(4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) ÷ 6 = 5.7
Next, find the absolute deviation of each value from the mean:
|4.8 - 5.7| = 0.9
|5.9 - 5.7| = 0.2
|6.2 - 5.7| = 0.5
|10.8 - 5.7| = 5.1
|1.2 - 5.7| = 4.5
|6.4 - 5.7| = 0.7
Then, find the mean of these absolute deviations:
(0.9 + 0.2 + 0.5 + 5.1 + 4.5 + 0.7) ÷ 6 ≈ 2.5
Therefore, the mean absolute deviation of the dataset is approximately 2.5.
What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.
To find the sum of the absolute deviations, first subtract the mean from each data point:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Then, sum these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 121.1
Therefore, the sum of the absolute deviations of the dataset is approximately 121.1.
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Then, sum these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 121.1
Therefore, the sum of the absolute deviations of the dataset is approximately 121.1.
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