To find the maximum value of the function F(x), we first need to determine where the maximum occurs. The function F(x) is a quadratic function in the form of ax^2 + bx + c, where a = 16, b = 32, and c = 20.
The maximum or minimum value of a quadratic function ax^2 + bx + c occurs at x = -b/(2a). Plugging in the values of a and b into the formula, we get:
x = -32 / (2*16) = -1
Therefore, the maximum value of the function F(x) occurs at x = -1. To find the maximum value of the function, plug in x = -1 into the function:
F(-1) = 16(-1)^2 + 32(-1) + 20
F(-1) = 16 + (-32) + 20
F(-1) = 4
Therefore, the maximum value of the function F(x) is 4.
What is the maximum value of this function
F(x)=16x^2+32x+20
1 answer