what is the maximum speed with which a car can round a turn of radius of 80.0m on a flat road if the coefficient of friction between tires and the road is .700?
My teacher said two substitutions and I don't have a mass. Thanks (:
1 answer
Centipetal force = frictional force mv2/r=Rmu m will be canceled and thus v will be equal to under root of ugr putting the values 80*700*10=560000 taking the under root answer will be 748.33
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