mv²/R= F(fr)
F(fr)=μN=μmg
mv²/R= μmg
μ= v²/Rg
Follow up
v= sqrt(μ•R•g) =
=sqrt(0.8•71•9.8) =23.6 m/s
What is the maximum speed with which a 1150-kg car can round a turn of radius 71 m on a flat road if the coefficient of static friction between tires and road is 0.80?
May someone walk me through this problem step by step? Thank you
*The equation friction coefficient= v^2/Rg does not make any sense. Because, I do not have a velocity.
1 answer