Asked by Jayesh
What is the maximum speed for a car to safely negotiate a 30 banked curve of 60 m radius if there is a coefficient of static friction of 0.35?
Answers
Answered by
bobpursley
The weight of the car parallel to the bank: mgCosTheta
friction : mg*Mu*sinTheta
centrepetal force up the bank
mv^2/r*cosTheta
Normal force component of centripetal force adding to weight:
mv^2/r*mu*SinTheta.
forces up the bank=forces down
friction+weightdownbank=centripal force up
mv^2*mu*Sintheta+mg*mu*CosTheta+mg*sinTheta=mv^2/r* CosTheta
solve for v.
friction : mg*Mu*sinTheta
centrepetal force up the bank
mv^2/r*cosTheta
Normal force component of centripetal force adding to weight:
mv^2/r*mu*SinTheta.
forces up the bank=forces down
friction+weightdownbank=centripal force up
mv^2*mu*Sintheta+mg*mu*CosTheta+mg*sinTheta=mv^2/r* CosTheta
solve for v.
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