I assume that is 3.3% w/w Ag (not AgNO3) in the 4.8 L of solution. You don't tell me the density of the solution so I will assume the density of the solution is 1 g/mL so 4.8 L has a mass of 4,800 grams.
3.3% w/w means 3.3 g Ag/100 g solution. The g Ag in 4,800 g solution is
3.3 x (4,800 g/100 g) = ? g Ag in the 4.8 L. That's the most you can plate out if you plate all of it.
What is the maximum amount of silver in grams that can be plated out of 4.8L of an AgNO3 solution containing 3.3% Ag by mass?
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