1. Fnet=ma=Fs
Fnet=ma=usFn
Fnet=ma=usmg
mass cancels
a=usg
Please stop reposting your question
What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.82?
3 answers
well noone answered it and so i reposst it. thank you for your responnse but the last message was not needed.
The car moves forward by the reaction force from the ground, produced due to friction between tires and road. According to the Newton’s 3rd law
F12 = F21
F(net)max = F(friction)max
m•a = k• m•g
a = k• g = 0.82•9.8 = 8.04 m/s^2
F12 = F21
F(net)max = F(friction)max
m•a = k• m•g
a = k• g = 0.82•9.8 = 8.04 m/s^2
1 answer