To solve the problem, we need to first calculate the total mass and total amount of sucrose in the mixture.
Total mass = 225 g + 135 g = 360 g
Amount of sucrose in the first solution = 6.25% x 225 g = 14.06 g
Amount of sucrose in the second solution = 8.20% x 135 g = 11.07 g
Total amount of sucrose in the mixture = 14.06 g + 11.07 g = 25.13 g
The mass percent of sucrose in the mixture is:
mass percent = (amount of sucrose ÷ total mass) x 100%
mass percent = (25.13 g ÷ 360 g) x 100% ≈ 6.98%
Therefore, the mass percent of sucrose in the mixture is approximately 6.98%.
What is the mass percent of sucrose in a solution Obtained by mixing 225 gram of An aqueous solution, that is 6.25% sucrose by mass with 135 gram. Of an aqueous solution that is 8.20% sucrose by Mass.
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