What is the mass pecent of an aqueous sodium hydroxide in which the mole fraction of NaOH is 0.162? The density of the solution is 1.3311 g/ mL

Answer 1

If we take 1 mole of solution, it will contain 0.162 mol NaOH and 1.00-0.162 = 0.838 mol H2O.
Convert 0.162 mole NaOH to grams.
Convert 0.838 mol H2O to grams.
mass percent = (g solute/total grams soln)*100 = ?
I don't think you need the density of the solution.

Answer 2

8.38% thank you very much