What is the mass of water required to fill a circular hot tub 3.4 m in diameter and 1.4 m deep?
Answer in units of kg.
2 answers
I got 0.2669 but wrong also
Ignoring you silly and meaningless school subject of
diameter/kg
volume = πr^2 h
= π(1.7)^2 (1.4) m^3
= 1000π(1.7)^2 (1.4) kg, (assuming 1 m^3 = appr 1000 kg with certain temperature restrictions)
= ....
diameter/kg
volume = πr^2 h
= π(1.7)^2 (1.4) m^3
= 1000π(1.7)^2 (1.4) kg, (assuming 1 m^3 = appr 1000 kg with certain temperature restrictions)
= ....
1 answer