What is the mass of the organic substance formed by heating of 21.0g of butanoate of ammonium, admitting that the reaction presents a yield of 50%?

Answer 1

CH3CH2CH2COONH4 + heat ==>CH3CH2CH2COOH + NH3
21.0 x (mm product acid/mm reactant) x 0.5 = ?
whee mm stands for molar mass.

Answer 2

thanks