How many mols Al(NO3)2 do you have?
That's 5.6g/molar mass Al(NO3)3 = ?
Then there are 9 mols O (not O2) for every 1 mol Al(NO3)3; therefore, mols Al(NO3)3 x 9 = mols O (not O2).
Finally mols O x 16 = grams O.
what is the mass of oxygen in a 5.6 g sample of Al(NO3)3.
1 answer