What is the mass of 11.7 moles of Be2(N03)2)

Answer 1

First, we need to find the molar mass of Be2(NO3)2.

The molar mass of Be (beryllium) is approximately 9.012 g/mol.
The molar mass of NO3 (nitrate) is approximately 14.007 + 3(16.00) = 62.007 g/mol.

Therefore, the molar mass of Be2(NO3)2 is:
2(9.012) + 2(62.007) = 18.024 + 124.014 = 142.038 g/mol

Now, to find the mass of 11.7 moles of Be2(NO3)2:
mass = moles x molar mass
mass = 11.7 mol x 142.038 g/mol
mass = 1661.216 g

Therefore, the mass of 11.7 moles of Be2(NO3)2 is 1661.216 grams.