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What is the mass? Density= 6 g/mL Volume= 7 mL

(1 point)
Responses

42 g
42 g

13 g
13 g

1 g
1 g

42 mL

11 answers

To find the mass, you can use the formula:

\[ \text{Mass} = \text{Density} \times \text{Volume} \]

Given:

  • Density = 6 g/mL
  • Volume = 7 mL

Now, substitute the values into the formula:

\[ \text{Mass} = 6 , \text{g/mL} \times 7 , \text{mL} = 42 , \text{g} \]

So the mass is 42 g.

What is the density of a piece of wood that has a mass of 7 g and a volume of 1javascript:void(0)0 cm3 (1 cm3 = 1 mL, so 10 cm3 = 10 mL)? What is the density of the wood when the piece of wood is cut in half? (1 point) Responses 0.7 g/cm3 and 0.35 g/cm3 0.7 g/cm3 and 0.35 g/cm3 0.7 g/cm3 and still 0.7g/cm3 0.7 g/cm3 and still 0.7g/cm3 0.7 g/cm3 and 1.4 g/cm3 0.7 g/cm3 and 1.4 g/cm3 70 g/cm3 and still 70 g/cm3

To find the density of the piece of wood, you can use the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

  • Mass = 7 g
  • Volume = 10 cm³ (which is equivalent to 10 mL)

Now, substitute the values into the formula:

\[ \text{Density} = \frac{7 , \text{g}}{10 , \text{cm}^3} = 0.7 , \text{g/cm}^3 \]

Now, when the piece of wood is cut in half, the mass of each half will be \( \frac{7 , \text{g}}{2} = 3.5 , \text{g} \), and the volume of each half will be \( \frac{10 , \text{cm}^3}{2} = 5 , \text{cm}^3 \).

Now, calculate the density of each half:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{3.5 , \text{g}}{5 , \text{cm}^3} = 0.7 , \text{g/cm}^3 \]

So, the density of the wood is 0.7 g/cm³, and when the piece is cut in half, the density remains 0.7 g/cm³.

The correct response is:

0.7 g/cm³ and still 0.7 g/cm³.

What is the correct unit of measure for volume calculated in the question before?(1 point)
Responses

grams (g)
grams (g)

milliliters (mL)
milliliters (mL)

grams per milliliter (g/mL)
grams per milliliter (g/mL)

The correct unit of measure for volume is:

milliliters (mL)

Since volume is measured, the response that corresponds to the measurement of volume is milliliters (mL).

What is the Density? Mass=12 grams Volume=4mL
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Question 6
6. What is the correct unit of measure for density calculated in the question before?(1 point)
Responses

grams (g)
grams (g)

milliliters (mL)
milliliters (mL)

grams per milliliter (g/mL)

To find the density, you can use the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

  • Mass = 12 grams
  • Volume = 4 mL

Now, calculate the density:

\[ \text{Density} = \frac{12 , \text{grams}}{4 , \text{mL}} = 3 , \text{g/mL} \]

Now to answer the second part of your question regarding the correct unit of measure for density:

The correct unit of measure for density is:

grams per milliliter (g/mL).

Mass is the amount of matter in an object. Weight includes the downward pull of gravity. Would you weigh more, less, or the same on the moon? Why?(1 point)
Responses

You would weigh more because gravity is higher on the moon than on Earth
You would weigh more because gravity is higher on the moon than on Earth

You would weigh the same since gravity is the same on the moon as it is on Earth
You would weigh the same since gravity is the same on the moon as it is on Earth

You would weigh less since the gravity is less on the moon than on Earth

You would weigh less since the gravity is less on the moon than on Earth.

The gravitational pull on the Moon is about 1/6th that of Earth's, so if you were on the Moon, you would weigh significantly less than you do on Earth, even though your mass would remain the same.

According to the table below, what is the unknown metal if it has a mass of 17.8 g and a volume 2 cm3? (d=m/v)

(1 point)
Responses

Chromium
Chromium

Platinum
Platinum

Lead
Lead

Silver
Silver

Cobalt
Cobalt

To identify the unknown metal based on its mass and volume, you can calculate its density using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

  • Mass = 17.8 g
  • Volume = 2 cm³

Now plug in the values:

\[ \text{Density} = \frac{17.8 , \text{g}}{2 , \text{cm}^3} = 8.9 , \text{g/cm}^3 \]

Next, compare this calculated density (8.9 g/cm³) to the known densities of the metals in your options:

  • Chromium: 7.19 g/cm³
  • Platinum: 21.45 g/cm³
  • Lead: 11.34 g/cm³
  • Silver: 10.49 g/cm³
  • Cobalt: 8.90 g/cm³

The calculated density of 8.9 g/cm³ matches closely with the density of Cobalt.

So, the unknown metal is Cobalt.