What is the loop that forms after many iterations when the initial value of g is 1.72?
g(x)= -2|x-2|+4
I tried to do this but it isn't looping so I think I'm doing it wrong. Help!
3 answers
It "loops" again at iteration ^13; where you get 2.24, likewise at iteration ^3. And again at iteration ^14, where you get 3.52, likewise at ^4. I am unsure if this is the definition of the "loop". My book doesn't explain if a loop is where you keep getting the same number after a certain iteration, or you will "loop" back around the iteration and then keep going? Can you please tell me if I'm right? Thank you in advance.
Not sure what you want. Do you mean that g is replaced by the previous value of g, so that
g(n+1) = -2|g(n)-2|+4
??
Otherwise, how do you get any looping activity?
g(n+1) = -2|g(n)-2|+4
??
Otherwise, how do you get any looping activity?
4 years and one day later, my best answer is to do loop-de-loops on a rollercoaster. math sucks
2 answers