Write the equation and balance it.
Convert g of both heptane and oxygen to mols. mols = grams/molar mass
One at a time, convert heptane to mols CO2 (as if you had all the oxygen needed); then convert oxygen to mols CO2 (as if you had all the heptane needed). Compare the two values. The correct value will be the SMALLER value of CO2 and the reagent producing that value will be the limiting reagent.
What is the limiting reactant of 4000 grams of heptane is combusted with 7000 grams of oxygen?
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