Asked by Mickeyyyy
What is the length of the radius of a circle with a central angle of 255° that intercepts an arc with length 52 m?
Use π=3.14 in your calculation.
how would i solve this? please help!
Use π=3.14 in your calculation.
how would i solve this? please help!
Answers
Answered by
Reiny
arc length = rØ, where r is the radius and Ø is the central angle in radians.
255° = (255/180)π radians = 17π/12
17π/12 r = 52
r = 52(12)/(17π)
= 624/(17π) m
= 11.6838... m using my calculator value of π
or even more simple:
2πr/360 = 52/255
2πr = (52/255)(360)
r = (52/255)(360/2π) = 624/(17π) , same as before
( I always wonder why would a text insist of using π = 3.14 unless it is a very old text? You are probably using a calculator anyway in these calculations, every calculator I have seen lately has a value of π built-in correct to about 10 decimal places)
255° = (255/180)π radians = 17π/12
17π/12 r = 52
r = 52(12)/(17π)
= 624/(17π) m
= 11.6838... m using my calculator value of π
or even more simple:
2πr/360 = 52/255
2πr = (52/255)(360)
r = (52/255)(360/2π) = 624/(17π) , same as before
( I always wonder why would a text insist of using π = 3.14 unless it is a very old text? You are probably using a calculator anyway in these calculations, every calculator I have seen lately has a value of π built-in correct to about 10 decimal places)
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