What is the lenght of the hypotenuse of a 30-60-90 triangle if the side opposite the 60-degree angle is 6 square root of 3?

3 answers

In a 30-60-90 triangle, the ratios of the lengths of the sides are as follows:

  • The side opposite the 30-degree angle (let's call it \( a \)) is \( x \).
  • The side opposite the 60-degree angle (let's call it \( b \)) is \( x\sqrt{3} \).
  • The hypotenuse (let's call it \( c \)) is \( 2x \).

From your question, we know that the side opposite the 60-degree angle \( b \) is \( 6\sqrt{3} \). According to the properties of a 30-60-90 triangle, we can set up the equation:

\[ b = x\sqrt{3} \]

Setting \( b = 6\sqrt{3} \), we have:

\[ x\sqrt{3} = 6\sqrt{3} \]

To solve for \( x \), divide both sides by \( \sqrt{3} \):

\[ x = 6 \]

Now that \( x \) is known, we can find the length of the hypotenuse \( c \):

\[ c = 2x = 2(6) = 12 \]

Thus, the length of the hypotenuse is \( \boxed{12} \).

u sure

Yes, let's confirm the steps to ensure the solution is correct.

In a 30-60-90 triangle, the relationships between the sides are as follows:

  • The side opposite the 30-degree angle (let's call it \( a \)) is \( x \).
  • The side opposite the 60-degree angle (let's call it \( b \)) is \( x\sqrt{3} \).
  • The hypotenuse (let's call it \( c \)) is \( 2x \).

You stated that the side opposite the 60-degree angle is \( 6\sqrt{3} \). Therefore, we can set up the equation:

\[ b = x\sqrt{3} \]

Substituting \( b = 6\sqrt{3} \), we have:

\[ x\sqrt{3} = 6\sqrt{3} \]

To isolate \( x \), we divide both sides by \( \sqrt{3} \):

\[ x = 6 \]

Next, we find the length of the hypotenuse \( c \) using the relation \( c = 2x \):

\[ c = 2(6) = 12 \]

So, the length of the hypotenuse of the triangle is indeed \( \boxed{12} \). If you have any further questions or need additional clarification, feel free to ask!