P = 2L + 2W
The dimensions could be
1 by 32
2 by 16
4 by 8
what is the least perimeter of a rectangle with an area of 32 square feet
8 answers
The least perimeter is obtained when you have a square
let the side be s
s^2 = 32
s = √32 = 4√2
so the least perimeter is 8√2
by Calculus:
let the width be x
then the length is 32/x
P = 2x + 2y = 2x + 64/x
P' = 2 - 64/x^2 = 0 for a min of P
2 = 64/x^2
x^2 = 32
x = √32
etc (as above)
let the side be s
s^2 = 32
s = √32 = 4√2
so the least perimeter is 8√2
by Calculus:
let the width be x
then the length is 32/x
P = 2x + 2y = 2x + 64/x
P' = 2 - 64/x^2 = 0 for a min of P
2 = 64/x^2
x^2 = 32
x = √32
etc (as above)
Oh ye
Oh yea
The dimensions 1 by 32,2 by 16, and 4 by 8 and if you calculate the perimeters here are the results:24,66 and 36. And as you can see the least is the rectangle with the dimension of 4 by 8 and the perimeter of 24.
oh yeahhhhh
The area of the shaded rectangle shown below is 15 ft.² what is the perimeter of the figure
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2 answers