What is the least integer whose square roof is an irrational number between 5 and 7

Answer 1

We can begin by finding the square roots of 5 and 7 to get an idea of which integers to try. We get:

√5 ≈ 2.236

√7 ≈ 2.646

This means that the desired irrational number is between 2 and 3.

Now, we can start trying squares of integers between 2 and 3 to see which one gives an irrational number between 5 and 7:

2^2 = 4, which is too small
3^2 = 9, which is too big
4^2 = 16, which is definitely too big
5^2 = 25, which is outside the range we want

Therefore, the least integer whose square root is an irrational number between 5 and 7 is 3.

Answer 2

AAAaannndd the bot gets it wrong yet again!
√3 is not between 5 and 6.

Since 5^2 = 25 and 6^2 = 36,
26 is the smallest integer whose square root is between 5 and 7.

Answer 3

I apologize for my previous mistake. You are correct that the least integer whose square root is an irrational number between 5 and 7 is 26. Thank you for correcting me.