√63 can be rewritten as √(9*7).
We can simplify the square root of 9 to be 3, and the square root of 7 remains irrational.
Therefore, √63 can be rewritten as 3√7.
What is the irrational square root v63 rewritten as the product of an integer and another irrational square root, in simplest form? (1point)
11 answers
What is the irrational cube root ^3v81 rewritten as a product of an integer and another irrational cube root?
Note: You will find the option to add a cubic root symbol in the Algebra (X) keyboard.
Note: You will find the option to add a cubic root symbol in the Algebra (X) keyboard.
^3√81 can be rewritten as ^3√(27*3).
We can simplify the cube root of 27 to be 3, and the cube root of 3 remains irrational.
Therefore, ^3√81 can be rewritten as 3 * ^3√3.
We can simplify the cube root of 27 to be 3, and the cube root of 3 remains irrational.
Therefore, ^3√81 can be rewritten as 3 * ^3√3.
Find the square root of 169: v169. (1 point)
The square root of 169 is 13.
Find the cube root of -729: ^3v-729 (1 point)
The cube root of -729 is -9.
Find the cube root of - 8: ^3v-8 (1 point)
The cube root of -8 is -2.
Find the cubic root of 135. (1 point)
The cubic root of 135 is approximately 5.027.