what is the irrational square root of 28 simplfied

Answer 1

To simplify the square root of 28, we can factor it into its prime factors.

1. First, find the prime factorization of 28: \[ 28 = 4 \times 7 = 2^2 \times 7 \]

2. We can then take the square root: \[ \sqrt{28} = \sqrt{2^2 \times 7} = \sqrt{2^2} \times \sqrt{7} = 2\sqrt{7} \]

Thus, the simplified form of \(\sqrt{28}\) is \(2\sqrt{7}\). Since \(\sqrt{7}\) is an irrational number, \(2\sqrt{7}\) is also irrational.