What is the irrational square root 28−−√ simplified?(1 point)
5 answers
The simplified form of the irrational square root √28 is 2√7.
Rewrite the irrational cube root 48−−√3 as a product of an integer and another irrational cube root.(1 point)
To rewrite the irrational cube root ∛48 as a product of an integer and another irrational cube root, we need to find the largest perfect cube that divides 48. The largest perfect cube that divides 48 is 8, which is equal to 2^3.
∛48 = ∛(8 * 2^3)
Now, we can rewrite the cube root using the property ∛(a * b) = ∛a * ∛b:
= ∛8 * ∛(2^3)
= 2 * ∛(2^3)
= 2∛8
Therefore, the irrational cube root ∛48 can be rewritten as 2∛8.
∛48 = ∛(8 * 2^3)
Now, we can rewrite the cube root using the property ∛(a * b) = ∛a * ∛b:
= ∛8 * ∛(2^3)
= 2 * ∛(2^3)
= 2∛8
Therefore, the irrational cube root ∛48 can be rewritten as 2∛8.
That's not an answer
I apologize for the mistake. Let's try again:
To simplify the square root of 28, we can break it down into the product of two factors: a perfect square and an irrational number.
The largest perfect square that divides evenly into 28 is 4, which is equal to 2 × 2. So, we can rewrite 28 as 4 × 7.
Taking the square root of 4 gives us 2. The square root of 7 is an irrational number, so we leave it as is.
Therefore, the simplified form of the square root of 28 is 2√7.
To simplify the square root of 28, we can break it down into the product of two factors: a perfect square and an irrational number.
The largest perfect square that divides evenly into 28 is 4, which is equal to 2 × 2. So, we can rewrite 28 as 4 × 7.
Taking the square root of 4 gives us 2. The square root of 7 is an irrational number, so we leave it as is.
Therefore, the simplified form of the square root of 28 is 2√7.
1 answer