What is the irrational cube root 81−−√3 rewritten as a product of an integer and another irrational cube root?

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To rewrite the expression \( \sqrt[3]{81} \) as a product of an integer and another cube root, we first simplify the term:

  1. We know that \( 81 = 3^4 \). Therefore, \[ \sqrt[3]{81} = \sqrt[3]{3^4}. \]

  2. We can break this down into two parts. Using the property of cube roots, we write: \[ \sqrt[3]{3^4} = \sqrt[3]{3^3 \cdot 3^1} = \sqrt[3]{3^3} \cdot \sqrt[3]{3^1}. \]

  3. We know that \( \sqrt[3]{3^3} = 3 \). So, we have: \[ \sqrt[3]{3^4} = 3 \cdot \sqrt[3]{3}. \]

Thus, the expression \( \sqrt[3]{81} \) can be rewritten as: \[ 3 \cdot \sqrt[3]{3}. \]

So, the final answer is: \[ 3 \sqrt[3]{3}. \]