The cube root of 81 can be written as 3, since 3^3 = 81. So, we can rewrite ∛81 as ∛(3^3).
Therefore, the expression ∛81−−√ can be rewritten as 3 −−√ = ∛(3^3)−−√ = 3∛1 = 3(1) = 3.
Therefore, the irrational cube root ∛81−−√3 is rewritten as a product of an integer (3) and another irrational cube root (∛1).
What is the irrational cube root 81−−√3 rewritten as a product of an integer and another irrational cube root?
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