The irrational cube root 𝑤=40−−√3 can be rewritten as the product of an integer and another irrational cube root by factoring out a perfect cube.
First, we need to find a perfect cube that can be factored out from 40. The largest perfect cube that is less than or equal to 40 is 27 which is equal to 3^3.
So, we can write 40 as 27 * 40/27.
Now we can rewrite the expression 𝑤=40−−√3 as follows:
𝑤=27 * 40/27−−√3
This can be further simplified as:
𝑤=27−−√(40/27 * 3)
Therefore, the irrational cube root 𝑤=40−−√3 can be rewritten as the product of an integer (27) and another irrational cube root (√(40/27 * 3)).
What is the irrational cube root 40−−√3 rewritten as a product of an integer and another irrational cube root?(1 point)
1 answer