What is the irrational cube root 40−−√3 rewritten as a product of an integer and another irrational cube root?(1 point) Responses 85–√3 8 root index 3 start root 5 end root −25–√3 negative 2 root index 3 start root 5 end root 210−−√3 2 root index 3 start root 10 end root 25–√3
1 answer
The irrational cube root of 40 can be rewritten as 2 root(3)(10).