To rewrite the irrational cube root √[3](40) as a product of an integer and another irrational cube root, we need to find a perfect cube that divides 40.
The largest perfect cube that divides 40 is 8, which is equal to 2^3.
Thus, we can rewrite the irrational cube root √[3](40) as 2√[3](5).
Therefore, the correct response is: 2 root index 3 start root 5 end root
What is the irrational cube root 40−−√3 rewritten as a product of an integer and another irrational cube root?(1 point) Responses −25–√3 negative 2 root index 3 start root 5 end root 85–√3 8 root index 3 start root 5 end root 25–√3 2 root index 3 start root 5 end root 210−−√3
1 answer
1 answer