To rewrite the irrational cube root √16 3 as a product of an integer and another irrational cube root, we can first simplify the expression.
√16 3 can be rewritten as (∛16)^(1/3).
We know that the cube root of 16 is 2, as 2^3 = 16.
Thus, (∛16)^(1/3) can be simplified to 2^(1/3).
Therefore, √16 3 rewritten as a product of an integer and another irrational cube root is 2^(1/3).
What is the irrational cube root √16 3
rewritten as
a product of an integer and another irrational cube
root?
1 answer