What you want is an equation for x in terms of y. That will be the inverse functuon.
I will assume that the log is to base e.
y = ln (x+1)^2
e^y = (x+1)^2
x+1 = sqrt (e^y) = e^(y/2)
x = e^(y/2) - 1
Switching variables, the inverse function can be written
f^-1(x) = e^(x/2) -1
What is the invers of:
y=2log(x+1)
and please explain this to me..not just an answer.
3 answers
thanks
inverse of y=ln(x)+4
how would i do this?
how would i do this?