To find the interquartile range (IQR), we first need to find the first quartile (Q1) and the third quartile (Q3).
Step 1: Arrange the numbers in increasing order: 18, 19, 22, 22, 25, 25, 26, 31, 32, 34, 37, 37, 37.
Step 2: Find Q1 by locating the median (the middle value) of the lower half of the numbers. In this case, Q1 is the median of 18, 19, 22, 22, 25. The median of these numbers is 22.
Step 3: Find Q3 by locating the median (the middle value) of the upper half of the numbers. In this case, Q3 is the median of 31, 32, 34, 37, 37. The median of these numbers is 34.
Step 4: Calculate the IQR by subtracting Q1 from Q3. In this case, IQR = 34 - 22 = 12.
Therefore, the interquartile range for this set of numbers is 12.
The correct answer is not among the choices provided.
what is the interquartile range for this set of numbers
18,19,22,22,25,25,26,31,32,34,37,37,37
answer
a.12.5
b.13.3
c.19.0
d.26.0
3 answers
Jack has the following scores on exams in his math class.
81, 87, 93, 89, 61, 81
If he wants to make his performance sound as good as possible, which measure should he use—the mean, the median, or the mode of his exam grades when he talks about how he is doing? Explain.
In you response, make sure to:
calculate the mean,
calculate the median, and
calculate the mode of his exam grades
compare and pick the measure that makes his performance sound as good as possible.
81, 87, 93, 89, 61, 81
If he wants to make his performance sound as good as possible, which measure should he use—the mean, the median, or the mode of his exam grades when he talks about how he is doing? Explain.
In you response, make sure to:
calculate the mean,
calculate the median, and
calculate the mode of his exam grades
compare and pick the measure that makes his performance sound as good as possible.
To determine which measure Jack should use to make his performance sound as good as possible, we need to calculate the mean, median, and mode of his exam grades.
Exam scores: 81, 87, 93, 89, 61, 81
1. Mean: The mean is calculated by adding up all the numbers and dividing by the total count. Summing up the exam scores, we get 81 + 87 + 93 + 89 + 61 + 81 = 492. Dividing by 6 (the total count), the mean is 492/6 = 82.
2. Median: The median is the middle value of a set of numbers when arranged in ascending order. Sorting the exam scores in ascending order, we get 61, 81, 81, 87, 89, 93. The median is 87, which is the middle value.
3. Mode: The mode is the number(s) that occur most frequently in a set of numbers. In this case, the mode is 81 because it appears twice, more than any other number in the set.
Considering the measures:
- The mean is 82.
- The median is 87.
- The mode is 81.
To make his performance sound as good as possible, Jack should use the median of his exam grades (87) when talking about how he is doing. The median is not affected by extreme values (outliers) like the mean is. In this case, the lower score of 61 would make the mean lower, but it does not affect the median. Therefore, by using the median, Jack can emphasize his relatively high score of 87, making his performance sound better.
Exam scores: 81, 87, 93, 89, 61, 81
1. Mean: The mean is calculated by adding up all the numbers and dividing by the total count. Summing up the exam scores, we get 81 + 87 + 93 + 89 + 61 + 81 = 492. Dividing by 6 (the total count), the mean is 492/6 = 82.
2. Median: The median is the middle value of a set of numbers when arranged in ascending order. Sorting the exam scores in ascending order, we get 61, 81, 81, 87, 89, 93. The median is 87, which is the middle value.
3. Mode: The mode is the number(s) that occur most frequently in a set of numbers. In this case, the mode is 81 because it appears twice, more than any other number in the set.
Considering the measures:
- The mean is 82.
- The median is 87.
- The mode is 81.
To make his performance sound as good as possible, Jack should use the median of his exam grades (87) when talking about how he is doing. The median is not affected by extreme values (outliers) like the mean is. In this case, the lower score of 61 would make the mean lower, but it does not affect the median. Therefore, by using the median, Jack can emphasize his relatively high score of 87, making his performance sound better.
1 answer