To complete the square for the equation \( x^2 = -2x + 63 \), we first rearrange it into a standard form:
-
Move the \( -2x \) term to the left side: \[ x^2 + 2x = 63 \]
-
Now, to complete the square, we take the coefficient of \( x \) (which is 2), divide it by 2 and square it: \[ \left( \frac{2}{2} \right)^2 = 1 \]
-
Add this squared value to both sides of the equation: \[ x^2 + 2x + 1 = 63 + 1 \]
-
This simplifies to: \[ (x + 1)^2 = 64 \]
Now, the intermediate step after completing the square is: \[ (x + 1)^2 = 64 \]
This is the form you were looking for.