Asked by david
what is the integral of x/(1+x^2)^2 dx This is a question of a past AP exam of calculus BC
i know i have to use the substitution method where u=(1+x^2), du=2xdx. I have to find the integral but i'm just focused on the coefficient because i get a different answer for that part
then you set the integral to .5(int)1/u^2 du,
but my answer choice on the AP exam test says that instead of 1/2 as the coefficient, it's 1/4 and i don't see where the 4 comes from.
i know i have to use the substitution method where u=(1+x^2), du=2xdx. I have to find the integral but i'm just focused on the coefficient because i get a different answer for that part
then you set the integral to .5(int)1/u^2 du,
but my answer choice on the AP exam test says that instead of 1/2 as the coefficient, it's 1/4 and i don't see where the 4 comes from.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.