sin(x) tan(x) = sinĀ²(x)/cos(x) = (1-cosĀ²(x))/cos(x) = sec(x) - cos(x)
Now you can probably handle it, yes?
what is the integral of {sin(x)tan(x)}
i tried turning tan(x) into sin(x)/cos(x) then doing u substitutions but i always have an extra sin(x) left.
can you help me pleeeease
2 answers
wooow, i cant believe ive been staring at it this long and couldn't see this. thanks!!