for constant acceleration:
V = Vo + a t
so for a = g = -9.8 m/s^2
V = 0 - 9.8 t = -98 meters/second
average = (Vo+V)/2 = (0-98)/2 = 49 m/s
distance = average velocity * time = 490 meters
what is the instantaneous velocity of a free falling object 10s after it is released from a postion of rest?
what is its average velocity during this 10s interval?
how far will it fall during this time?
1 answer
1 answer