y = 8/x
y' = -8/x^2
now plug in x = -3
the avg rate of change is
change in y
------------------
change in x
So, that would be
(y(4)-y(-3))/(4-(-3))
Now just plug in the numbers
What is the instantaneous slope of y =8/x at x = -3?
What is the average rate of change of y with respect to x over the interval [-3, 4] for the function y = 2x + 2?
The surface area, S, of a sphere of radius r feet is S = S(r) = 4πr2. Find the instantaneous rate of change of the surface area with respect to the radius r at r = 2.
I am a little confused here can anyone show the work and steps please.
3 answers
i have no idea
kjbujbh;