What is the indefinite integral of 6/(x ln(2x)??
3 answers
6ln(ln(2x))+C
Let u = ln(2x)
du = [2/(2x)] dx = dx/x
6 dx/(x ln(2x)) = 6/u du
= 6 ln u
= 6 ln(ln(2x)) (+ arbitrary constant C)
du = [2/(2x)] dx = dx/x
6 dx/(x ln(2x)) = 6/u du
= 6 ln u
= 6 ln(ln(2x)) (+ arbitrary constant C)
I did the integration in the next to last line. It does not equal the preceding line.